x^2+(x+2)^2=(2x-2)2

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Solution for x^2+(x+2)^2=(2x-2)2 equation: 



x^2+(x+2)^2=(2x-2)2

We move all terms to the left:

x^2+(x+2)^2-((2x-2)2)=0



We calculate terms in parentheses: -((2x-2)2), so:

(2x-2)2

We multiply parentheses

4x-4

Back to the equation:

-(4x-4)



We get rid of parentheses

x^2+(x+2)^2-4x+4=0

We add all the numbers together, and all the variables

x^2-4x+(x+2)^2+4=0

We move all terms containing x to the left, all other terms to the right

x^2-4x+(x+2)^2=-4

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